The answer to this question is 12
Step-by-step explanation:
Here you solve for length width and height, which multiplied equal volume. The only constant you have is that the width of the prism is 1/3 of its length.
WIDTH: 3 centimeters
LENGTH: Since the width is 1/3 of the length, 3 is 1/3 of something. So divide 3 by 1/3 to get 9. You can also just multiply 3 by 3.
HEIGHT: The height is half of the width, which is 3. Therefore 3 divided by 2 is 1.5.
Now multiply the values. 3 multiplied by 9 multiplied by 1.5
The answer is 40.5
CENTIMETERS!!!
DO NOT FORGET THE UNIT
Answer:
5x
Step-by-step explanation:
UwU
Answer: ![\sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125x%5E3%7D)
.
Step-by-step explanation: Given radical expression
![\sqrt[3]{5x} \times \sqrt[3]{25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D)
.
According to the product property of roots.
![\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%20%5Ctimes%20b%7D)
On applying above rule, we get
![\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D%20%3D%20%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D)
5 × 25 = 125 and
Therefore,
![\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D%3D%20%5Csqrt%5B3%5D%7B125x%5E3%7D)
<h3>So, the correct option would be second option
.</h3>
Answer:
240 houses
Step-by-step explanation:
Given that:
Number of streets = 4
Length of each street = 3/4 miles long
Street is divided into lots with one house built per lot
1 mile = 5289 feets
3/4 miles = (3/4) * 5280 = 3960 feets
Hence, street is 3960 feets long
Since each lot must have at least 65 feet frontage along the street:
Number of lots per street :
Length of street / frontage length
3960 ft / 65 ft = 60.92
Hence, maximum number of lots per street = 60 lots per street
Maximum number of houses in New neighborhoods :
Number of lots per street × number of streets
= 60 × 4
= 240 houses
