All categories

1 year ago

Funique513 tt insta twitter follow for points I follow back too

Mathematics

2 answers:

frozen [14]1 year ago

7 0

Answer:

Snap is Cris_on60fps

Step-by-step explanation:

Insta boiwithno there is a curse word but is starts with a b

hichkok12 [17]1 year ago

3 0

I couldn’t find you on Inst. M’I missing something?

You might be interested in

A student with two summer jobs earns $10 per hour at a cafe and $8 per hour at a market the student would like to earn at least

o-na [289]

$80*10=$800. Hope this helps

5 0

2 years ago

A regular hexagon has a side length of 6 units.

valkas [14]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What are the coordinates of point h?

xz_007 [3.2K]

-1,3 that’s easy u should definitely pay attention in class

7 0

2 years ago

Read 2 more answers

Simplify 5 - 8 +3 * 9

Snezhnost [94]

Answer:

-25

Step-by-step explanation:

5-8+(3*9)=

=5-8+(27)=

=5-8+27=

=5-35=

=-25

6 0

2 years ago

Read 2 more answers

Y=x2-2x-5<br> Change to vertex form

MaRussiya [10]

The vertex form is $y=(x-1)^{2} -6$

Step-by-step explanation:

The given equation $y=x^{2} -2x-5$ is a parabola. The vertex of the parabola is of the form $y=ax^{2} +bx+c$

The parameters of the parabola are $a=1, b=-2$ and $c=-5$

The vertex of the x-coordinate is given by $x=\frac{-b}{2a}$

Thus, substituting the values of a and b in $x=\frac{-b}{2a}$ , we get,

$\begin{aligned}x &=\frac{-(-2)}{2(1)} \\&=\frac{2}{2} \\x &=1\end{aligned}$

Now, substituting $x=1$ in $y=x^{2} -2x-5$ , we get,

$\begin{aligned}y &=1^{2}-2(1)-5 \\&=1-2-5 \\y &=-6\end{aligned}$

Thus, the vertex is $(1,-6)$

The equation of parabola to be in vertex form is $y=a(x-h)^{2} +k$

where a is the coefficient of $x^{2}$ , h is vertex of the x-coordinate and k is the vertex of the y-coordinate.

Hence, $a=1, h=1$ and $k=-6$

Thus, substituting the values in the equation of the vertex form,

$y=1(x-1)^{2} -6\\y=(x-1)^{2} -6$

Hence, the vertex form is $y=(x-1)^{2} -6$

8 0

3 years ago