Answer: The probability that the fruit is an orange or a pear is .
Step-by-step explanation:
Given : Emily has 12 fruits in her bowl.
She has 3 apples, 5 bananas, 1 pear and 3 oranges.
A fruit is selected at random.
P(orange) =
P(pear)=
Since both events of selecting orange and pear are mutually exclusive , so
The probability that the fruit is an orange or a pear = P(orange) + P(pear)
Therefore , the probability that the fruit is an orange or a pear is .
Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have
case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1
case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2
Answer: The y-value of the vertex is
Step-by-step explanation: we know that
The equation of a vertical parabola into vertex form is equal to
where
(h,k) is the vertex of the parabola
In this problem we have
-----> this a vertical parabola open upward
Convert to vertex form
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Factor the leading coefficient
Complete the square. Remember to balance the equation by adding the same constants to each side
Rewrite as perfect squares
The vertex is the point
The y-value of the vertex is
Answer:
2nd answer
Step-by-step explanation:
For this case we have the following multiplication:
We can rewrite this multiplication in the following way:
From here, we apply the distributive property.
We have then:
Therefore, Jack's strategy is:
Write the number in an expanded form and then apply the distributive property.
Answer:
Jack's strategy is:
Write the number in an expanded form and then apply the distributive property.