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1 year ago

HELP THIS IS DUE TOMORROW

Mathematics

2 answers:

butalik [34]1 year ago

8 0

Answer:

Step-by-step explanation:

AAS

∠A = ∠D Given

∠B = ∠C Given

BC = CB Reflexive property

ΔABC ≅ ΔDCB AAS Congruent

Vikentia [17]1 year ago

6 0

Answer:

f it not possible to prove the triangle are conqrugent.

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the distance a jet travels varies directly as the number of hours it flies. A jet traveled 2875 miles in 5 hours. What is the co

skelet666 [1.2K]

Answer:

k = 575

Step-by-step explanation:

let d be distance and h time.

Given d varies directly as h then the equation relating them is

d = kh ← k is the constant of variation

To find k use the condition d = 2875, h = 5, then

2875 = 5k ( divide both sides by 5 )

k = 575

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3 years ago

A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. The

solniwko [45]

Answer:

f(x) = 26500 * (0.925)^x

It will take 7 years

Step-by-step explanation:

A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.

To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.

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3 years ago

20 POINTS WILL MARK AS BRAINLIEST AND SAY THANKS In 2000, the cost of many items increased because the increase in the cost of g

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Let the cost of gasoline in the year 2000 be represented b the equation
y = a + b*x
where
x = months, counted from January
y = cost, dollars

The given data in the table is
Month: Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
x, months: 1 2 3 4 5 6 7 8 9 10 11 12
y, dollars: --- --- --- --- 1.76 2.13 --- --- --- --- --- ---

When x = 5, y = 1.76.
Therefore
a + 5b = 1.76 (1)

When x = 6, y = 2.13
Therefore
a + 6b = 2.13 (2)

Subtract equation (1) from (2).
a + 6b - (a + 5b) = 2.13 - 1.76
b = 0.37

From (1), obtain
a = 1.76 - 5b
= 1.76 - 5*0.37
= -0.09

The required equation is
y = 0.37x - 0.09
The graph shows the line, with the given data for May and June.

Answer: D. y = 0.37x - 0.09

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2 years ago

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47=20+(2x+y)
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The answer is b - 4(x) + 4(2)

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2 years ago

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