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2 years ago

Eliminate the parameter. x = 7t, y = t + 4

Mathematics

2 answers:

kenny6666 [7]2 years ago

8 0

Answer:

7y = x + 28

Step-by-step explanation:

Given x = 7t and y = t + 4

Here t is the parameter Now to remove it express one of it in terms of the variables (like x or y)

Given x = 7t

from this we can write $t=\frac{x}{7}$

Now substitute this value in the second equation

y = t + 4

$y=\frac{x}{7}+4$

Therefore the parameter is eliminated.

Rama09 [41]2 years ago

6 0

Answer:

y = x/7 + 4

Step-by-step explanation:

7y = x + 28

7y<em>(/7)</em> = x<em>(/7) </em>= 28<em>(/7)</em>

y = x/7 + 4

Hope this helps!

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Nataly [62]

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<h3>Quadratic equation</h3>

From the question, we are to determine the roots of the given equation

The given equation is

x² -5x +2 = 0

Using the formula method,

$x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}$

In the given equation,

a = 1, b = -5, c = 2

Putting the values into the formula,

$x =\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(2) } }{2(1)}$

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$x =\frac{5 + \sqrt{17} }{2}$ OR $x =\frac{5 - \sqrt{17} }{2}$

$x =\frac{5 + 4.12}{2}$ OR $x =\frac{5 - 4.12}{2}$

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x = 4.56 OR x = 0.44

Hence, the roots of the equation is x = 4.56 OR x = 0.44

Learn more on Quadratic equation here: brainly.com/question/8649555

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