Answer: 9cm
Explanation:
Refractive index can also be defined as the ratio of the real depth to the apparent depth.
Given that the
Real depth = 12 m
Refractive index of water = 1.33
Refractive index of air = 1.00
nair/nwater = real depth/apparent depth
Substitute all the parameters into the formula
1.33/1 = 12/ apparent depth
Cross multiply
1.33 Apparent depth = 12
Apparent depth = 12/1.33
Apparent depth = 9.02 cm
Therefore, A submerged swimmer in the pool sees the tip of the triangle at 9cm approximately distance above the water.
Answer:
Im not really sure but Id say weather .
Explanation:
