Answer:
Δ JKL is similar to Δ ABC ⇒ D
Step-by-step explanation:
Similar triangles have equal angles in measures
In ΔABC
∵ m∠A = 15°
∵ m∠B = 120
∵ The sum of the measures of the interior angles of a Δ is 180°
∴ m∠A + m∠B + m∠C = 180°
→ Substitute the measures of ∠A and ∠B
∵ 15 + 120 + m∠C = 180
→ Add the like terms in the left side
∴ 135 + m∠C = 180
→ Subtract 135 from both sides
∴ 135 - 135 + m∠C = 180 - 135
∴ m∠C = 45°
The similar Δ to ΔABC must have the same measures of angles
If triangles ABC and JKL are similar, then
m∠A must equal m∠J
m∠B must equal m∠K
m∠C must equal m∠L
∵ m∠J = 15°
∴ m∠A = m∠J
∵ m∠L = 45°
∴ m∠C = m∠L
∵ m∠J + m∠K + m∠L = 180°
→ Substitute the measures of ∠J and ∠L
∵ 15 + m∠K + 45 = 180
→ Add the like terms in the left side
∴ 60 + m∠K = 180
→ Subtract 60 from both sides
∴ 60 - 60 + m∠K = 180 - 60
∴ m∠K = 120°
∴ m∠B = m∠K
∴ Δ JKL is similar to Δ ABC
Answer:
f(x)=x2
g(x)=3x+2
(f+g)(x)=x2+3x+2=(x+1)(x+2)
Step-by-step explanation:
Explanation:
It depends on the fraction
The midpoint is the middle, which is the average. So you would do 6.9+1.7 which is 8.6 then divide it by 2, giving you the answer 4.3.
4.3 inches of rainfall is the midpoint
Answer:
Option A.)−4
Step-by-step explanation:
we have
4x+5y=-12 -----> equation A
-2x+3y=-16 -----> equation B
Solve the system of equations by elimination
Multiply the equation B by 2
2*(-2x+3y)=-16*2
-4x+6y=-32 -----> equation C
Adds equation A and equation C
4x+5y=-12
-4x+6y=-32
-----------------
5y+6y=-12-32
11y=-44
y=-4