Answer:
4 possible outcomes
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
Let
x------> size of the event space
y-----> size of the sample space
so
In this problem
<em>The probability of choose a blue card is
</em>
substitute
<em>The probability of choose a green card is
</em>
substitute
<em>The probability of choose a red card is
</em>
substitute
<em>The probability of choose a yellow card is
</em>
substitute
The sum of the probabilities of the 4 possible outcomes is equal to
----> represent the 100%
<span>The <u>correct answers</u> are:
x=-3 and x=-8.
Explanation<span>:
We can first write this in standard form, ax</span></span>²<span><span>+bx+c=0. To do this, we will add 11x to both sides:
x</span></span>²<span><span>+24+11x=-11x+11x
x</span></span>²<span><span>+11x+24=0.
Now we can factor this. Look for factors of c, 24, that sum to b, 11. Factors of 24 are:
1 and 24 (sum 25)
2 and 12 (sum 14)
3 and 8 (sum 11)
4 and 6 (sum 10).
The factors we need are 3 and 8, since they sum to 11. This gives us factored form:
(x+3)(x+8)=0.
Using the zero product property, we know that in order to have a product of 0, one or both of the factors must be 0. This means we have:
x+3=0 or x+8=0.
Solving the first equation:
x+3-3=0-3
x=-3.
Solving the second equation:
x+8-8=0-8
x=-8.</span></span>
Answer:
Step-by-step explanation:
Answer:
a = 10, b = 6, c = 2, d = 0
Step-by-step explanation:
Substitute the appropriate values of x into the equation and evaluate
x = - 3 : y = 4 - 2(- 3) = 4 + 6 = 10 → a
x = - 1 : y = 4 - 2(- 1) = 4 + 2 = 6 → b
x = 1 : y = 4 - 2(1) = 4 - 2 = 2 → c
x = 2 : y = 4 - 2(2) = 4 - 4 = 0 → d
Answer:
Step-by-step explanation:
The foci are horizontally aligned.
horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
center (h,k)
vertices (h±a,k)
length of minor axis = 2b
foci (h±c,k), c² = a²-b²
Apply your data and solve for h, k, a, and b.
foci (±3√19, 6)
h = 0
k = 6
Length of minor axis = 2b = 10
b = 5
foci (h±3√19, 6)
c = 3√19
c³ = a² - b²
171 = a² - 25
a² = 196
x²/196 + (y-6)²/25 = 1