The patch doubles in size each day so, on the 47th will be half the size than on the 48th day
We use the following trigonometric identity to answer the question:
sin^ 2 (theta) + cos^ 2 (theta) = 1
We substitute the values:
sin ^ 2 (theta) + 0.73 = 1
We cleared:
sin ^ 2 (theta) = 1-0.73
sin ^ 2 (theta) = 0.27
Answer:
a possible value of sin ^ 2 (theta) is:
c.0.26 (nearest option)
Answer:
26 - 7 i. hopefully this helps!
Answer:
Maximum is 4
Step-by-step explanation:
M(x) is quadratic function, so we need to fin maximum.
m(x)=-x(x-4)
m(x)=-x^2+4x
To find a maximum we need to find m’
M’(x)=-2x+4
M’(x)=0 if x=2
The maximum is in the point x=2
M(2)=-2(2-4)=4
40/1 = 80/2 = 120/3 = 160/4 = 200/5 = 240/6 = 280/7 = 320/8 = 360/9 = 400/10 = 440/11 = 480/12 = 520/13 = 560/14 = 600/15 = 640/16 = 680/17 = 720/18 = 760/19 = 800/20
If that helps?