Answer:
30
Step-by-step explanation:
IJ/HK = IG/HG = 2
IJ/HK = (v+30)/v = 2
v + 30 = 2v
v = 30
Answer: the length of one edge of the square base of the second container is 6 inches.
Step-by-step explanation:
The formula for determining the volume of a rectangular container is expressed as
Volume = length × width × height
Considering the first container,
Length = 12 inches
Width = 8 inches
Height to which the water is filled is 6 inches.
Therefore, volume of water in the container is
12 × 8 × 6 = 576 inches³
Considering the second container,
Height of water = 16 inches
Let L represent the length of the square base. Then the area of the square base is L²
Volume of water would be 16L²
Since the water in the first container was poured into the second container, then
16L² = 576
L² = 576/16 = 36
L = √36
L = 6 inches
Answer:
bout 7
Step-by-step explanation:
Law of sines can be used to solve this problem:
(note - let x represent the missing side length.)
1. set up proportion.
sin 90°/25 = sin 55<span>°/x
2. solve.
(x) sin 90</span>° = (25) sin 55<span>°
(x) sin 90 </span>°/sin 90° = (25) sin 55° / sin 90<span>°
</span>
x = 20.4788011072
rounded to nearest tenth = 20.5
