Answer:
(1,1)
Step-by-step explanation:
The choices are not visible, however are unnecessary to solve this problem.
Given y = 3x - 2 and y = -2x + 3
[Set them equal to each other]
3x - 2 = -2x + 3
[Find x]
3x + 2x - 2 = 3
3x + 2x = 5
5x = 5
x = 1
[Plug x = 1 to both equations to check and find y]
y = 3x - 2
y = 3(1) - 2 = 3 - 2 = 1
y = -2x + 3
y = -2(1) + 3 = -2 + 3 = 1
Both are equal to y = 1 when x = 1
The point is then: (1,1)
Use this version of the Law of Cosines to find side b:
b^2 = a^2 + c^2 − 2ac cos(B)
We want side b.
b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)
After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.
Try it....
The median is 44 (the center line)
Answer:
(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step-by-step explanation:
Using the identity for the difference of 2 squares;
a^2 - b^2 = (a - b)(a + b)
we put a^2 = 81x^8 and b^2 = 1 giving
a = 9x^4 and b = 1, so:
81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)
Applying the difference of 2 squares to 9x^4 - 1:
= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
KCC
7 units 7-4=3 (-9)-(-5)=
-9+5=(-4)
3+(-4)= 7
