If B and b are the two alleles , B + b = 1 and B ^2 +2 Bb + b ^2 = 1.
If 16% of mice are homozygous black , B ^ 2 =0 .16, meaning B = 0 .4 and b = 1 - 0. 4 = 0 .6 .
Answer = Notice how you don't even need to know that 24% of the mice are heterozygous .
Answer:
The correct answer is b. C6H12O6 -> 2 C3H4O3+2 H+
Explanation:
Glycolysis occurs in both the condition aerobic and anaerobic so it does not require oxygen. In glycolysis, one glucose molecule is converted into two pyruvate( 2 C3H4O3) and two 2 ATP, 2NADH, and 2 H₂O are produced.
Initially, 2NAD⁺ is produced during glycolysis which is reduced to produce 2NADH and 2 H⁺. Therefore the correct equation is C6H12O6 -> 2 C3H4O3+2 H+.
Then this pyruvate is used in the Kreb cycle which is required for the complete breakdown of glucose into carbon dioxide and water and this process occurs in aerobic conditions. Complete oxidation is important to produce more energy from partially oxidized glucose.
It is just called: a simple fracture. BUT when the bone does pierce the skin it's called a compound fracture. <span />
I would guess C, hope that helps!
