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2 years ago

Which of these atoms has the largest number of neutrons in the nucleus?

Chemistry

1 answer:

viktelen [127]2 years ago

8 0

Holonium and Gadolinium has the highest number of neutrons in the nucleus.

Looking at the atoms listed;

Dysprosium has 66 protons

Holonium has 67 protons

Neodymium has 60 protons

Europium has 63 protons

Gadolinium has 64 protons

Then,

Number of neutrons = Mass number - number of protons

For Dysprosium

157 - 66 = 91 neutrons

For Holonium

162 - 67 = 95 neutrons

For Neodymium

149 - 60 = 89 neutrons

For Europium

148 - 63 = 85 neutrons

For Gadolinium

159 - 64 = 95 neutrons

Hence, Holonium and Gadolinium has the highest number of neutrons in the nucleus.

Learn more: brainly.com/question/14156701

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the physical and chemical properties of the products are different from the reactants

Explanation:

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2 years ago

Alveoli are tiny sacs of air in the lungs. Their average diameter is 4.50 × 10−5 m. Calculate the uncertainty in the velocity of

Arisa [49]

<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is $4.424\times 10^{-5}m/s$

<u>Explanation:</u>

The diameter of the molecule will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p=\frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $4.50\times 10^{-5}m$

$\Delta p$ = uncertainty in momentum = $m\Delta v$

m = mass of oxygen molecule = $5.30\times 10^{-26}kg$

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s$

Hence, the uncertainty in the velocity of oxygen molecule is $4.424\times 10^{-5}m/s$

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2 years ago