Answer:
k = [F2]² [PO]² / [P2] [F2O]²
Explanation:
In a chemical equilibrium, the equilibrium constant expression is written as the ratio between the molar concentration of the products over the molar concentration of the reactants. Each species powered to its reaction coefficient. For the equilibrium:
P2(g) + 2F2O(g) ⇄ 2PO(g) + 2F2(g)
The equilibrium constant, k, is:
k = [F2]² [PO]² / [P2] [F2O]²
So they can tell what exact species it is.
Answer:
Mass
Step-by-step explanation:
Usually, you plot the independent variable along the horizontal (x) axis and the dependent variable along the vertical (y) axis.
Marcia's teacher plotted the mass of the sample along the x-axis and volume along the y-axis.
The mass is the independent variable, because that is <em>what the teacher varied</em>.
The volume is the <em>dependent variable</em>, because it <em>depends</em> on the mass.
Sample number is <em>wrong</em>, because it is not a variable.
Substance is <em>wrong</em>, because all samples consist of the same substance.
Density is <em>wrong</em>, because it is constant. It is the slope of the graph.
Answer to this question is C. Regarding the volume.
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
