Describe how the graph above shows aconstant speed
1 answer:
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Answer:
(a) Wavelength is 0.436 m
(b) Length is 0.872 m
(c) 11.518 m/s
Solution:
As per the question:
The eqn of the displacement is given by:
(1)
n = 4
Now,
We know the standard eqn is given by:
(2)
Now, on comparing eqn (1) and (2):
A = 1.22 cm
K =
where
A = Amplitude
K = Propagation constant
= angular velocity
Now, to calculate the string's wavelength,
(a)
where
K = propagation vector
(b) The length of the string is given by:
(c) Now, we first find the frequency of the wave:
Now,
Speed of the wave is given by:
Answer:
Explanation:
The attached figure shows the whole description. Considering the applied force is 100 N.
The acceleration of both blocks A and B,
Firstly calculating the mass m using the second law of motion as :
F = ma
m is the mass
m = 125 kg
It suddenly encounters a surface that supplies 25.0 N a friction, F' = 25 N
So, the new acceleration of the block is . Hence, this is the required solution.
