Answer:
V=27.24 m/s
Explanation:
We need to apply the linear momentum conservation theorem:
The velocity of the eagle its defined by its two components:
because speed is a scalar value:
When the object is at rest, there is a zero net force due the cancellation of the object's weight <em>w</em> with the normal force <em>n</em> of the table pushing up on the object, so that by Newton's second law,
∑ <em>F</em> = <em>n</em> - <em>w</em> = 0 → <em>n</em> = <em>w</em> = <em>mg</em> = 112.5 N ≈ 113 N
where <em>m</em> = 12.5 kg and <em>g</em> = 9.80 m/s².
The minimum force <em>F</em> needed to overcome <u>maximum</u> static friction <em>f</em> and get the object moving is
<em>F</em> > <em>f</em> = 0.50 <em>n</em> = 61.25 N ≈ 61.3 N
which means a push of <em>F</em> = 15 N is not enough the get object moving and so it stays at rest in equilibrium. While the push is being done, the net force on the object is still zero, but now the horizontal push and static friction cancel each other.
So:
(a) Your free body diagram should show the object with 4 forces acting on it as described above. You have to draw it to scale, so whatever length you use for the normal force and weight vectors, the length of the push and static friction vectors should be about 61.3/112.5 ≈ 0.545 ≈ 54.5% as long.
(b) Friction has a magnitude of 15 N because it balances the pushing force.
(c) The object is in equilibrium and not moving, so the acceleration is zero.
The current in a parallel circuits is not constant throughout the circuit. It varies in each path of a parallel circuit. The components that is place across each other have the same voltage in a parallel circuit. Remember, V=RI.
Answer:
a = 0.827468
Explanation:
given,
half life of radium-224 = 3.66 days
now,
t is the time
A₀ is the amount at t = 0
at t = 0 , A(0) = 1
A(3.66) = 1/2
at t = 3.66
taking log both side
3.66 log (a) = log (0.5)
log a = -0.0822
now,
a = 0.827468