Here as we know that there is no loss of energy
so we can say that maximum kinetic energy will become gravitational potential energy at its maximum height
So here we have
here we have
v = 20 m/s
m = 8000 kg
now from above equation we have
so maximum height is 20.4 m
Answer:
The height of the image is, h' = 6.0 cm
The image is erect.
Explanation:
Given data,
The object distance, u = -5 cm
The focal length of convex lens, f = 10 cm
The object height, h = 3 cm
The lens formula,
v = -10 cm
The magnification factor of lens
m = 2
h' = 6 cm
The height of the image is, h' = 6 cm
The image is erect.
Divide the distance traveled by the time it took:
(100 m) / (4.2 s) ≈ 23.8 m/s