Answer:
C. A negative particle outside the nucleus
Explanation:
Answer : Radius of Earth is 6,340 Km.
Explanation
It is given that,
Tangential velocity of Earth at the equator, v = 465 m/s
Centripetal acceleration at the equation is, 
We know that the relation between centripetal acceleration and tangential velocity is :
..........(1)
Where,
v is tangential velocity
r is the radius
Putting all values in equation (1)
or
The Earth's radius is 6,340 Km. Hence, this is the required solution.
Answer:
<h2>3.46km</h2>
Explanation:
Hey there!!!, the figure 2.5 as stated in the question cannot be found, even though we have enough information to proceed.
given
speed of kangaroo s= 65 km/h
time taken t= 3.2 mins
distance d=?
Since we are expected to find the distance covered in km we need to convert the time to hours first and solve
converting minutresto hours we have
60 minutes ----- 1 hour
3.2 minutes-------Xhours
cross mutiply we have
X= 3.2/60= 0.053 hour
Now we can calculate the distance as
s=d/t
d=s*t
d= 65*0.0533
d=3.46km
Hence the Kangaroo we travel a distance of 3.46km
Answer:
Option A is correct.
when it is used in a circuit. its terminal voltage will be less than 1.5 V.
Explanation:
The terminal voltage of the battery when it is in use in circuits drops lower than the 1.5 V rating given to it due to internal resistance.
All batteries give internal resistances when used in circuits. The internal resistance (though very small) is usually modelled as connected in series with the battery. It is due to some form of interference from the chemical makeup of the battery.
Normally, while the battery is fresh, the voltage (V) obtained at its terminals when connected in series with a resistor of resistance R is V = IR; where I is the current flowing in this circuit.
But once the interenal resistance (r) of the battery comes into play,
V = I₁ (r + R)
The current in the circuit evidently drops (that is I₁ < I) and V = (I₁r + I₁R)
The voltage across the terminals of the battery is no longer V but is now (V) × [R/(R+r)] which is less than the initial V and it reduces as the internal resistance, r, increases.
Hope this Helps!!!
Given what we know, we can confirm that when the student moves the compressed coiled spring faster but <u>keeps everything else the same</u>, she is effectively increasing the wave frequency of the model.
<h3>What we know about wave frequency.</h3>
- Wave frequency measures number of times waves pass through a specific point over an interval of time.
- This refers to the speed at which waves are passing, which increases when the student moves the coiled spring faster.
- The amplitude of the wave model is given by the coil's length.
- The crest and wavelengths are given by the shape and length of the coil respectively.
We can confirm that since the student did not make any changes to the shape of the coil, its compression, or its length, she did not affect the amplitude, crest, or wavelength for the model. Therefore, only the frequency of the wave model increased with this change.
To learn more about Wave frequency visit:
brainly.com/question/14588679?referrer=searchResults
