Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation:
Answer:
X=0
Step-by-step explanation:
What you do is - 82400 from 102650 and you should get your answer
A) because when they are equal it means that their y has the same value, which means their intersection point.
B) You should take all integers from (-2, 2) which are: -2, -1, 0, 1, 2 and put them one by one in the example:
x = -2
y1 = 4^-(-2) = 4^2 = 16
y2 = 2^(-(-2) + 1) = 2^(2+1) = 2^3 = 8
y1 ≠ y2 => so x=-2 isn't our answer
-------------------------------------------------------
x = -1
y1 = 4^-(-1) = 4^1 = 4
y2 = 2^(-(-1) + 1) = 2^(1+1) = 2^2 = 4
y1 = y2 => so our answer will be x = -1
-------------------------------------------------------
x = 0
y1 = 4^-(0) = 4^0 = 1
y2 = 2^(-(0) + 1) = 2^(0+1) = 2^1 = 2
y1 ≠ y2 => so x=0 isn't our answer
--------------------------------------------------------------
x = 1
y1 = 4^-(1) = 4^(-1) = 1/4
y2 = 2^(-(1) + 1) = 2^(-1+1) = 2^0 = 1
y1 ≠ y2 => so x=1 isn't our answer
--------------------------------------------------------------
x = 2
y1 = 4^-(2) = 4^(-2) = 1/16
y2 = 2^(-(2) + 1) = 2^(-2+1) = 2^(-1) = 1/2
y1 ≠ y2 => so x=2 isn't our answer
Which means that our final answer is: x=-1
C) You should draw both graphics, and their intersection point (x) will be the answer.
I hope it helped.
Answer:
C
Step-by-step explanation: