The reaction between K₂SO₄(aq) and SrI₂(aq) produces KI(aq) and SrSO₄(s) as products.
The reaction is
K₂SO₄(aq) + SrI₂(aq) → KI(aq)+ SrSO₄(s)
To balance the equation both side of the reaction should have same number of atoms in each element.
Right hand side of the reaction has 1 K, 1 I, 1 Sr, 1 S and 4 O atoms while 2 K, 2 I, 1 Sr,1 S and 4 O present in left hand side of the reaction.
Hence, number of I atoms and number of K atoms are not balanced.
To balance the K atoms we should add 2 before KI. Then I atoms will be 2 at the right hand side.
Hence, the balanced reaction equation is
K₂SO₄(aq) + SrI₂(aq) → 2KI(aq)+ SrSO₄(s)
The atoms that would be expected to be diamagnetic in the ground state is magnesium
The magnetism of an atom refers to its electronic configuration. A diamagnetic atom is an atom whose electrons are all paired.
A paired electron is an electron that occurs in pairs in its orbital shell.
At their respective ground state, the electronic configuration of the given elements are as follows:
The electronic configuration of magnesium is 1s²2s²2p⁶3s². As such its a diamagnetic atom.
The electronic configuration of Potassium is 1s²2s²2p⁶3s²3p⁶4s¹. Hence, Potassium has one unpaired electron in its outermost shell.
The electronic configuration of Chlorine is 1s²2s²2p⁶3s²3p⁵. Hence, Chlorine has one unpaired electron in its outermost shell.
The electronic configuration of Cobalt is 1s²2s²2p⁶3s²3p⁶3d⁷4s². Hence, the unpaired electrons of Cobalt in its outermost shell are three.
Therefore, the atoms that are diamagnetic in the ground state is magnesium.
Learn more about diamagnetic atoms here:
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Answer:
A.) False B.)False C.) True D.) False E.) False
Explanation:
