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2 years ago

6

From a collection of 52 store customers, 3 are to be chosen to receive a special gift. How many groups of 3 customers are possib

le?

1 answer:

eimsori [14]2 years ago

3 0

Answer:

132,600 possibilities

Step-by-step explanation:

The first one chosen can be 1 of 52

The 2nd one chosen is 1 out 51

And the 3rd chosen is 1 out 50

So...

52 x 51 x 50 = 132,600

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the five members of the traynor family each buy train tickets during the train ride each family member buys a box one for $6.50

NeX [460]

Answer:

$43.20

Step-by-step explanation:

If each family member buys one ticket and one lunch, then for ticket price t we have the total expenditure as ...

5(t +6.50) = 248.50

t +6.50 = 49.70 . . . . . divide by 5

t = 43.20 . . . . . . . . . . subtract 6.50

The price of each train ticket is $43.20.

8 0

2 years ago

Solve. (K+1)(k-5)=0<br> Explin how to solve ???

Anna71 [15]

Alright remember, if any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
k+1=0
k-5=0
Set the first factor equal to 0 and solve
k=-1
Set the next factor equal to 0 and solve
k=5
The final solution is all the values that make (k+1)(k-5)=0 true.
k=-1, 5

Hope this helped you out :)

5 0

2 years ago

Read 2 more answers

a certain shade of blue is made by mixing 1.5 quarts of blue paint with 5 quarts of white paint. If you need a total of 16.25 ga

Law Incorporation [45]

we know the blue and white paints are on a 1.5 : 5 ratio, thus, if we have a total of 16.25 gallons of paint to be split along that ratio, we can simply divide 16.25 by (1.5+5) and distribute accordingly.

$\bf \cfrac{blue}{white}\qquad \stackrel{ratio}{1.5:5}\qquad \cfrac{1.5}{5}~\hspace{5em}\cfrac{1.5\cdot \frac{16.25}{1.5+5}}{5\cdot \frac{16.25}{1.5+5}}\implies \cfrac{1.5\cdot \frac{16.25}{6.5}}{5\cdot \frac{16.25}{6.5}} \\\\\\ \cfrac{1.5\cdot 2.5}{5\cdot 2.5}\implies \cfrac{3.75}{12.5}\qquad \qquad \boxed{\stackrel{blue}{3.75}~:~\stackrel{white}{12.5}}$

5 0

2 years ago

Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?

Eddi Din [679]

Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

$|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }$

The magnitude of vecor v is given to be 10. So we can write:

$10= \sqrt{ (-1-x)^{2} + (5-y)^{2} } \\ \\ 100=(-1-x)^{2} + (5-y)^{2}$

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.

The point in option d, satisfies the equation.

$100=(-1+7)^{2} +(5+3)^{2} \\ \\ 
100=36+64 \\ \\ 
100=100$

Thus, the answer to this question is option D

7 0

2 years ago

PTG has side lengths of 18 cm, 27 cm, and 13 cm. which type of triangle is PTG? The answer is obtuse.

Verizon [17]

To know what kind of triangle is it. use the pythagorean theorem:
A^2 + B^2 = C^2,
where C is the longest side of the triangle
if it satisfies the equation then it is a right triangle
if it does not then A^2 + B^2 > C^2 so it is acute triangle
if A^2 + B^2 < C^2 it is obtuse triangle

18^2 + 13^2 ? 27^2
324 + 169 ? 729
493 < 729 so it is obtuse triangle

3 0

2 years ago