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2 years ago

Can someone please help me with #26 ASAP.. It is due tomorrow.. Please help ASAP

Mathematics

1 answer:

OlgaM077 [116]2 years ago

6 0

The answer is 5 because if you answer it correctly then you’ll get 5

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Whats the step by step process to solve 3(×-9)=30

Sergio [31]

step 1 : 3 • (x - 9) - 30 = 0 Step 2 :Step 3 :Pulling out like terms :

3.1 Pull out like factors :

3x - 57 = 3 • (x - 19)

Equation at the end of step 3 : 3 • (x - 19) = 0 Step 4 :Equations which are never true :

4.1 Solve : 3 = 0

This equation has no solution.
A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2 Solve : x-19 = 0

Add 19 to both sides of the equation :
 x = 19

One solution was found : x = 19

7 0

2 years ago

Read 2 more answers

Which equation, when graphed, has x-intercepts at (8,0) and (-2, 0) and a y-intercept at (0, -48)?

n200080 [17]

Answer:

f(x)=-3(x-8)(x+2)

Step-by-step explanation:

f(8)=-3(8-8)(8+2)=-3×0×10=0

f(-2)=-3(-2-8)(-2+2)=-3×(-10)×0=0

f(0)=-3×(0+8)×(0+2)=-3×8×2=-48

4 0

2 years ago

Joshua currently does a total of 8 pushups each day. He plans to increase the number of pushups he does each day by 2 pushups un

alekssr [168]

He currently does 8, and is increasing by 2, so our equation will be

2x+8=30

Subtract the 8 over

2x=22

Divide by 2 on both sides

X=11

It will take 11 days

6 0

2 years ago

Read 2 more answers

2. What is the solution of (-8x)= 32?

raketka [301]

Answer:

x=-4

Step-by-step explanation:

divide 32 by 8 and move the negative sign to the result.

6 0

2 years ago

velikii [3]

Given data:

Volume of the prism A = 2080 $c m^{3}$

Let us find the ratio of the volume of prisms given in the diagram:
$\frac{ V_{A}}{V_{B}} = \frac{8^{3}}{4^{3}}$
$\frac{ V_{A}}{V_{B}} = 8$

Since the condition is:
The volume of Prism A = The volume of Prism B
Therefore,
The ratio of their volumes should be 8.
$\frac{ V_{A}}{V_{B}} =8$

Since Volume of A = 2080 $cm^{3}$

Plug-in the value, you would get:

$\frac{2080}{8}} = V_{B}$

Ans: Volume of B = 260 $cm^{3}$

7 0

3 years ago