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2 years ago

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A sewing machine sews at a constant rate of 1,500 stitches per minute. If the equation, y = 1,500x represents the relationship b

etween the number of minutes, x, and the total number of stitches, y, what is the independent and dependent variable? (EE.C.9b)

1 answer:

crimeas [40]2 years ago

5 0

Answer:

Step-by-step explanation:

x is the independent variable. y is the dependent variable.

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Point Q is the center of dilation. Line segment L M is dilated to created line segment L prime M prime. The length of L Q is 4 a

koban [17]

Answer:

The length of segment QM' = 6

Step-by-step explanation:

Given:

Q is the center of dilation

Pre-image (original image) = segment LM

New image = segment L'M'

The length of LQ = 4

The length of QM = 3

The length of LL' = 4

The original image was dilated with scale factor = 2

QM' = ?

To determine segment QM', first we would draw the diagram obtained from the given information.

Find attached the diagram

When a figure is dilated, we would have similar shape in thus cars similar triangles.

Segment L'M' = scale factor × length of LM

Let LM = x

L'M' = 2x

Using similar triangles theorem, ratio of their corresponding sides are equal.

QM/LM = QM'/L'M'

3/x = QM'/2x

6x = QM' × x

Q'M' = 6

The length of segment QM' = 6

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A High School booster club sets up an academic scholarship that is awarded to one student each year. The formula y=2700x can be

djyliett [7]

Answer:

$32,400

Step-by-step explanation:

We can just replace 12 for x in the equation y = 2700x

y = 2700x

y = 2700(12)

y = 32,400

The money paid after 12 years is $32,400

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A square has an area of 49 cm2. what is the length of each side?

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Answer: 24.5

Step-by-step explanation:

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2 years ago

In the diagram below, the circle has a radius of 25 inches. the area of the unshaded is 500pi in^2Determine and state the degree

Dmitriy789 [7]

$72^{\circ}$

1) In this question, we are going to make use of the formula for the area of that sector, to find the central angle.

2) So, let's write it out an expression involving the area of a circle, the unshaded area, and the shaded one and then plug into that the given data:

$\begin{gathered} A=\frac{\alpha}{360^{\circ}}\times\pi r^2 \\ A_{Unshaded}+A_{shaded}=A_{Circle} \\ 500\pi+\frac{\alpha}{360}\times\pi r^2=\pi r^2 \\ \\ 500\pi+\frac{α}{360}\pi25^2=25^2\pi \\ \\ 500\pi+\frac{125\piα}{72}=625\pi \\ \\ 500\pi +\frac{125\pi α}{72}-500\pi =625\pi -500\pi \\ \\ \frac{125\pi α}{72}=125\pi \\ \\ \frac{72\times \:125\pi α}{72}=72\times \:125\pi \\ \\ \frac{125\pi α}{125\pi }=\frac{9000\pi }{125\pi } \\ \\ α=72^{\circ} \\ \\ \end{gathered}$

Thus, the centra angle of that shaded area is 72º

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5 months ago