Answer:
percentage yield = 67%
Explanation:
Mass of Cu(NO₃)₂ = 15.25 g
Mass of NaOH = 12.75 g
Percentage yield = ?
Solution:
Cu(NO₃)₂ + 2NaOH → Cu(OH)₂ + 2NaNO₃
Moles of Cu(NO₃)₂:
Number of moles = mass/ molar mass
Number of moles = 15.25 g /187.56 g/mol
Number of moles = 0.08 mol
Moles of NaOH :
Number of moles = mass/ molar mass
Number of moles = 12.75 g / 40 g/mol
Number of moles = 0.32 mol
Now we will compare the moles of Cu(OH)₂ with NaOH and Cu(NO₃)₂. NaOH : Cu(OH)₂
2 : 1
0.32 : 1/2×0.32 = 0.16 mol
Cu(NO₃)₂ : Cu(OH)₂
1 : 1
0.08 : 0.08
The number of moles produced by Cu(NO₃)₂ are less so it will limiting reactant.
Mass of Cu(OH)₂:
Mass = number of moles × molar mass
Mass = 0.08 mol × 97.6 g/mol
Mass = 7.808 g
Theoretical yield = 7.808 g
Percent yield:
percentage yield = Actual yield/ theoretical yield × 100
percentage yield = 5.23 g/ 7.808 g × 100
percentage yield = 0.67 × 100
percentage yield = 67%
The nutrients that the body breaks down into basic units are carbohydrates, fats, and proteins. From carbohydrates comes glucose, your body's -- especially the brain's -- primary form of fuel; from fats we get glycerol and fatty acids, many of which are essential ingredients in hormones and the protective sheath in our brain that covers communicating neurons; and from proteins we get amino acids, which are the building blocks to lots of structures, including our blood, muscle, skin, organs, antibodies, hair, and fingernails.
Each of these nutrients travels down a different pathway, but all can eventually fuel the body's production of ATP (adenosine triphosphate), which is essentially our bodies' ultimate energy currency.
Answer:
0.486 L
Explanation:
Step 1: Write the balanced reaction
2 KCIO₃(s) ⇒ 2 KCI (s) + 3 O₂(g)
Step 2: Calculate the moles corresponding to 1.52 g of KCIO₃
The molar mass of KCIO₃ is 122.55 g/mol.
1.52 g × 1 mol/122.55 g = 0.0124 mol
Step 3: Calculate the moles of O₂ produced from 0.0124 moles of KCIO₃
The molar ratio of KCIO₃ to O₂ is 2:3. The moles of O₂ produced are 3/2 × 0.0124 mol = 0.0186 mol
Step 4: Calculate the volume corresponding to 0.0186 moles of O₂
0.0186 moles of O₂ are at 37 °C (310 K) and 0.974 atm. We can calculate the volume of oxygen using the ideal gas equation.
P × V = n × R × T
V = n × R × T/P
V = 0.0186 mol × (0.0821 atm.L/mol.K) × 310 K/0.974 atm = 0.486 L
Answer:
water and oceans
Explanation:
the moons creates tides as it goes around the
earth. This creates a bulge on the side of the earth.
https://www.google.com/imgres?imgurl=https%3A%2F%2Fdr282zn36sxxg.cloudfront.net%2Fdatastreams%2Ff-d%253A71e7747b2985faa97dd0428c0d0d35a7a8db33cb6b55e7e3d81da378%252BIMAGE_TINY%252BIMAGE_TINY.1&imgrefurl=https%3A%2F%2Fwww.ck12.org%2Fearth-science%2FTides%2Flesson%2FTides-HS-ES%2F&tbnid=FgLwu9bKOEkJOM&vet=12ahUKEwiO-b61j_XoAhUOq54KHccrCcQQMygIegUIARCXAg..i&docid=EI9-q7wLqid5CM&w=800&h=501&q=moon%20tides%20diagram&ved=2ahUKEwiO-b61j_XoAhUOq54KHccrCcQQMygIegUIARCXAg
