The atomic mass represented on an element tile on the Periodic Table

Which of these outdoor activities would you most likely participate in during the winter?

Elza [17]

Answer:

D.

Explanation:

Translation:

A. make a barbecue

B. organize a picnic

C. swimming in the pool

D. to go skiing

Barbecue is usually a summer activity, so we eliminate that.

It would be too cold for a picnic!

It would be too cold to go swimming, and that's more of a summer thing!

Skiing is a snow activity, and since it is winter, it is likely to know.

4 0

2 years ago

Help me plzz I need help

Sladkaya [172]

The is no picture???????

3 0

2 years ago

Any help with these questions would help i'm lost

SSSSS [86.1K]

Answer:

1. 31.25 mL

2. 1.98 g/L

3. 0.45 g/mL

Explanation:

For each of the problems, you need to perform unit conversions. You need to use the information given to you to convert to a specific unit.

1. You need volume (mL). You have density (g/mL) and mass (g). Divide mass by density. You will cancel out mL and be left with g.

(50.0 g)/(1.60 g/mL) = 31.25 mL

2. You are given grams and liters. You need to find density with units g/L. This means that you have to divide grams by liters.

(0.891 g)/(0.450 L) = 1.98 g/L

3. You have to find density again but this time with units g/mL. Divide the given mass by the volume.

(10.0 g)/(22.0 mL) = 0.45 g/mL

5 0

2 years ago

What are the two different ions present in the compound al(no3)3?

Aleks [24]

$Al^{3+}$ and $NO_3^{-}$

Aluminum nitrate is an ionic compound, meaning that it is made up cations and anions. By convention when writing the formula for an ionic compounds the cation part shall be placed in front the anions. Thus the cation would contain aluminum and the anion shall be a polyatomic nitrate ion consisting of nitrogen and oxygen. The bracket with subscript 3 attached resembles the ratio between the two species, aluminum ions and nitrate ions. For each aluminum ion in the compound there shall be three corresponding nitrate ions.

Aluminum form ions of charge +3 whereas nitrate ions are of charge -1. Write the charge of the ion as the superscript in reverse (i.e., write $3+$ as in $Al^{3+}$ and $-$ in $NO_3^{-}$ , omitting any 1.)

5 0

2 years ago

At STP (101.3 kPa, 0 °C), what volume would 2.00 moles of oxygen gas occupy? The gas constant is 8.31

lakkis [162]

Answer:

44.8 L

Explanation:

Ideal Gas Equation -

i.e.,

PV = nRT

where,

P = pressure

V = volume

n = moles

R = universal gas constant

T = temperature

Using the information given in the question, Volume of the gas can be calculated -

P = 101.3 kPa

V = ?

n = 2.00 moles

R = 8.31

T = 0 degree C = 273.15 K

Using the above data, and putting the data in the respective formula -

PV = nRT

101.3 kPa * V = 2.00 moles * 8.31 * 273.15 K

V = 44.8 L

Hence, the volume of the given gas = 44.8 L

4 0

2 years ago