What is the solution to this system of equations? 2t + w = 10 4t = 20 − 2w A. It has no solution. B. It has infinite solutions.
C. It has a single solution: t = 4, w = 2. D. It has a single solution: t = 2, w = 6. E. It has a single solution: t = 6, w = -2.
1 answer:
Answer:
<h3>B. It has infinite solutions</h3>
Step-by-step explanation:
Given the system of equations:
2t + w = 10 ..... 1
4t = 20 − 2w ... 2
From 1:
w = 10-2t ...3
Substitute 3 into 2 to have;
4t = 20 - 2(10-2t)
4t = 20-20+4t
4t = 4t
Let t = k
Substitute t = k into 1 and get w;
From 1: 2t + w = 10
2k + w =10
w = 10 - 2k
<em>k can take any integers. This shows that the solution to the equation is infinite</em>
<em></em>
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