2 years ago

What volume is occupied by 22.1 g of O2 at 52°C and a pressure of 1.63 atm?

1 answer:

Nutka1998 [239]2 years ago

3 0

U can use PV=nRT
where n=mass in grams/ molar mass
temp will be converted into kelvin by adding 273k
the value of R = 0.0821
try it by yourself :)

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What is the amount of heat energy absorbed when 36 grams of ice at -20oC is melted to water at 0oC?

Ulleksa [173]

Answer:

Q = 1461.6 J

Explanation:

Given data:

Mass of ice = 36 g

Initial temperature = -20°C

Final temperature = 0°C

Amount of heat absorbed = ?

Solution:

specific heat capacity of ice is 2.03 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 0°C - (-20°C)

ΔT = 20°C

Q = 36 g ×2.03 j/g.°C×20°C

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2 years ago

Ammonia gas decomposes to form nitrogen and hydrogen gases. NH3(g) → N2(g) 3H2(g) If the nitrogen gas is collected in a rigid 2

sveticcg [70]

Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas $(\rm N_{2})$ in the cylinder is 1.63 moles.

<h3>What is the ideal gas equation?</h3>

The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,

$\rm PV = nRT$

Where,

Pressure (P) = 2000 kPa

Volume (V) = 2L

Temperature (T) = 295 K

Gas constant (R)= 0.08206

Substituting values in the equation:

$\begin{aligned} \rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{2000 \times (\dfrac{1}{101.325}) \times 2}{0.08206 \times 295}\\\\&= 1.63\;\rm mol\end{aligned}$