Answer:
Ratio is 3:2
3CO = 2Fe or 1.5 CO = 1 Fe
Explanation:
Fe2O3 + 3CO = 2Fe + 3CO2
Fe2O3 = Iron (|||) oxide
CO = Carbon monoxide
Fe = Solid Iron
CO2 = Carbon dioxide
Excellent is already balanced.
10 Moles Fe and 15 Moles of CO2
5 Moles Fe2O3 + 15 Moles 3CO = 10 Moles Fe + 15 Moles 3CO2
What is the ratio of carbon monoxide to solid iron
Ratio is 3:2 or 1.5 CO = 1 Fe
It is Cobalt(II)chloride dihydrate. The value of x is 2.
First, we have to determine the mass of H₂O that was evaporated upon heating which will be = 2.00g - 1.56 g
= 0.435 g
So,
CoCl₂ + x.H₂O → CoCl₂.xH₂O
Molecular mass of CoCl₂ = 129.839 g/mol
Molecular mass of H₂O = 18 g/mol
Weight of sample after heating = 1.565 g
Weight of H₂O evaporated = 0.435 g
Hence,
x ≈ 2
So, it is Cobalt(II)chloride dihydrate.
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Answer:
9.033 × 10²³ molecules
Explanation:
Given data:
Mass of oxygen = 48.0 g
Number of molecules = ?
Solution:
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 48.0 g/ 32 g/mol
Number of moles = 1.5 mol
Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ molecules
1.5 mol × 6.022 × 10²³ molecules / 1mol
9.033 × 10²³ molecules
First, we require the combustion equation of propane:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We see that each mole of propane produces 4 moles of water.
Now, we calculate the moles of water required: 75 / 18.02
Moles required = 4.16
Moles of propane required for this are: 4.16 / 4 = 1.04 moles
Each mole of gas occupies 22.14 liters, so the volume of propane required are 1.04 * 22.14 = 23.03 L
23 L of propane are required
Answer:
List the set of all even numbers between 2 and 10, inclusive.
List the set of all even numbers between 2 and 10, inclusive.
Explanation:
