We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
Answer:
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Answer:
There are infinitely many solutions
Step-by-step explanation:
Firstly, I need to change f to x as the system won’t accept the word f
Let’s take a look at the question;
3 is less than x
The domain of our answer lies in the the range of values where we have numbers that are greater than 3
This means we can rewrite our inequality as x is greater than 3
Now, simply because we have an infinite amount of numbers which are greater than 3 of which x can take any of the values, we can conclude that the number of values we have for x are infinite and does not end
This makes us have infinitely many solutions for the value of x
Answer:
(a) a function, but not one-to-one
Step-by-step explanation:
The graph is of a function if it passes the vertical line test: a vertical line intersects the graph in at most 1 point.
The function is one-to-one if it passes the horizontal line test: a horizontal line intersects the graph in at most 1 point.
__
Here, the graph consists of a series of non-overlapping horizontal lines. It passes the vertical line test (is a function), but a horizontal line can intersect the graph in an infinite number of points (is not one-to-one).
The graph is a function, but not one-to-one.
<h3>
Answers: x = -17 and x = 64</h3>
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Explanation
Consider three scenarios:
- A) The value of x is the smallest of the set (aka the min)
- B) The value of x is the largest of the set (aka the max)
- C) The value of x is neither the min, nor the max. So 8 < x < 39.
These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.
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We'll start with scenario A.
If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}
The range is 56, so,
range = max - min
56 = 39 - x
56+x= 39
x = 39-56
x = -17 which is one possible answer
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If instead we go with scenario B, then x is the max and 8 is the min
range = max - min
56 = x - 8
56+8 = x
64 = x
x = 64 is the other possible answer
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Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.
Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.
