Answer:
There would be 24 dimes and 76 quarters.
Step-by-step explanation:
In order to find this, start by defining the number of dimes by x and the number of quarters as y. Now we can create a system of equations. Make the first about the total number of coins.
x + y = 100
Make the second about the amount of money.
.10x + .25y = 21.40
Now we can solve using elimination by multiplying the second equation by -4 and adding through.
x + y = 100
-.40x - y = -85.60
-----------------------
.60x = 14.4
x = 24
Now we can use the amount of dimes we have to find the number of quarters.
x + y = 100
24 + y = 100
y = 76
for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
We are given the two lines:
k (x) = (- 9 / 5) x + (5 / 2)
h (x) = (2 / 5) x - (7 / 6)
At the intersection of the two lines, we get that:
(- 9 / 5) x + (5 / 2) = (2 / 5) x - (7 / 6)
(2 / 5) x + (9 / 5) x = (5 / 2) + (7 / 6)
(11 / 5) x = 11 / 3
3 x = 5
x = 5 / 3
y = (2 / 5) (5 / 3) - (7 / 6)
y = 2 / 3 - 7 / 6
y = - 1 / 2
Therefore, we get that, for the lines k (x) = (- 9 / 5) x + (5 / 2) and h (x) = (2 / 5) x - (7 / 6), the solution for x will be 5 / 3 and y will be - 1 / 2.
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16m cubed - 10m squared......
take out the common factors
they both have a two that can go into it and both have two m's you can take out
so then it becomes
2m squared(8m-5) and thats your answer (: