Answer:
ω = 0.36 rev/s = 2.24 rad/s
Explanation:
First, we will find the time taken by the diver to reach the water. For this we use 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height = 9.6 m
Vi = initial vertical velocity = 0 m/s
t = time taken = ?
g = 9.8 m/s²
Therefore,
9.6 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t = √1.95 s²
t = 1.4 s
Now, the average angular speed of diver will be:
ω = No. of Revolutions/t
ω = 0.5 rev/1.4 s
<u>ω = 0.36 rev/s = 2.24 rad/s</u>
Answer:
that's your answer..
..f = \mu N
f = friction force
\mu = coefficient of friction
N = normal force
Answer:
The wave becomes longer and it would be a little bit more softer sound
Explanation:
Answer:
for the body to float, the density of the body must be less than or equal to the density of the liquid.
Explanation:
For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.
Weight is
W = mg
let's use the concept of density
ρ_body = m / V
m = ρ_body V
W = ρ_body V g
The thrust of the body is given by Archimedes' law
B = ρ_liquid g V_liquid
as the body floats the submerged volume of the liquid is less than or equal to the volume of the block
ρ_body V g = ρ_liquid g V_liquid
ρ_body = ρ liquid Vliquido / V_body
As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.
