Heat energy required to increase the temperature of water in bathtub is 12,546,000 Joules.
<h3>What is thermal energy?</h3>
The energy contained by an object by virtue of heating is known as thermal energy.
Given is the mass of water m = 150 kg, Temperature change ΔT = (40 -20)= 20 °C
The specific heat of water Cp =4182 J/kg.°C
Heat transfer Q =m x Cp x ΔT
Q = 150 x 4182 x 20
Q = 12,546,000 J
Thus, Heat energy required to increase the temperature of water in bathtub is 12,546,000 Joules.
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Answer:
Wavelength,
Explanation:
Given that,
Number of cycles in a spiral spring is 2.91 in every 3.67 s
The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s
To find,
Wavelength
Solution,
Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,
The wavelength of a wave is given by :
So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.
Answer: 2400m
Explanation: 2400m because 600 times 4 equals 2400
Answer:
It is found that W1 - W2 loss in weight of solid when immersed in water is equal to the weight of the water displaced by the body. This verifies Archimedes' principle.