The factors of 56: 1; 2; 4; 7; 8; 14; 28; 56
The factors of 84: 1; 2; 3; 4; 6; 14; 28; 42; 84
GCF(56; 84) = 28
See Quadratic Formula and Determinant's/Delta's formula
Answer:
The required probability is 0.533.
Step-by-step explanation:
Consider the provided information.
The actual weight of the chocolate has a uniform distribution ranging from 31 to 32.5 ounces.
Let x is the random variable for the actual weight of chocolate.
According to PDF function.
Where
It is given that ranging from 31 to 32.5 ounces.
Substitute a=31 and b=32.5 in above function.
We need to find the probability that a box weighs less than 31.8 ounces
Now according to PDF:
Hence, the required probability is 0.533.
<span>There are 56 possible combinations when drawing two chips. Remember that you cannot draw two of the same chips from the bag, so 11, 22, 33, 44, 55, 66, 77, and 88 are not possible. Therefore, 20 of 56 combinations are divisible by 3, or approximately 36 percent.
12,13,14,15,16,17,18
21,23,24,25,26,27,28
31,32,34,35,36,37,38
41,42,43,45,46,47,48
51,52,53,54,56,57,58
61,62,63,64,65,67,68
71,72,73,74,75,76,78
81,82,83,84,85,86,87</span>