Answer:
They cost the same amount
Step-by-step explanation:
Given
Lin: 
where x = 14
Max: 
for 14 days
Required
Which is less expensive?
Max charges has been given from the question as; $120 for 14 days.
To determine Lin's, we simply substitute 14 for x in
The above result of y shows that Max charges for 14 days is also $120.
<em>Hence, they (Lin and Max) cost the same because they both equal to $120 for 14 days</em>
As they vary from month to month, Luis's variable expenses are the utility bill, groceries, clothing and fuel.
Variable expenses is a concept in economics. They are costs that change due to an increase or decrease in the production volume, such as raw material costs.
The variable cost in money is obtained by multiplying, starting from a certain cost, the variable cost in kind by the price of the variable factor. The curves of average variable cost and marginal variable cost are deduced from the curve of variable cost in money according to geometric relationships.
Therefore, as they vary from month to month, Luis's variable expenses are the utility bill, groceries, clothing and fuel.
Learn more about maths in brainly.com/question/21694231
Answer:
Step-by-step explanation:
First of all let's notice that 
while our original polynomial is real. So we can rule out the even options B and D. At this point, if the polynomial has a factor of 
it means tha 
is a zero of the polynomial. Let's check both 2 (for option a) and -2 (for option c)
At this point 2 is a zero, and our final factoring is a
Answer:
The length of the shorter piece=0.35 m
Step-by-step explanation:
Let the lengths be as follow;
Shorter piece=x
Longer piece=15 cm longer than twice shorter piece(x)
Since 1 m=100 cm, 15 cm=15/100=0.15 m
Longer piece= (2×x)+0.15=2x+0.15
Total length=1.2 m
Total length=shorter piece+longer piece
Replacing;
1.2=x+2x+0.15
3x=1.2-0.15
3x=1.05
x=(1.05/3)=0.35
The length of the shorter piece=x=0.35
Let
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>
