The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.
<h3>What are the real solutions of the equation as given in the task content?</h3>
It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;
x² = 225
x = ± 15
Therefore, the real solutions of the equation are; +25 and -25.
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Answer:
72
Step-by-step explanation:
If SR and RU have the same length, a right angle, and a shared side, we know that they are congruent triangles using SAS (Side Angle Side). Our equation to find the perimeter would be SR + RU + UT + TS or 16 + 16 + 20 + 20(using our knowledge of the congruent triangles) = 72.
The angle is 90° degrees.
X-6y=6 slope: 1/6 y-intercept (0,1)
X= 0,6 y= -1, 0
X+3y+12=0 slope: 1/3
Y-intercept (0,4) x= -12, 0 Y= 0,4
8a-9b= 9/8 slope (0 ,7/8) x= -1,1 Y= -1/4,2
3a+b=7 1/3 (0,7/3) x= 4,7 Y=1,0
