List the constant(s) in 2ab + 8 + c

Which of the following scores has the better relative position ( as measured by the z score) a. A score of 53 on a test for whic

Kisachek [45]

Answer:

d. Cannot be determined with the information provided.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Finding the better relative position:

The score with the better relative position is the one with a higher z-score.

To find the z-score, the mean and the standard deviation is needed, and in this question, the standard deviation is not given, and thus, the correct answer is given by option d.

3 0

2 years ago

Select the correct answer from each drop-down menu.

Ivahew [28]

In 20 minutes, John can wrap 10 small boxes and Hank can wrap 12 small boxes. So, Hank can wrap more small boxes in 20 minutes than John can.

Step-by-step explanation:

Given,

John wraps;

2 small boxes = 4 minutes

1 small box = $\frac{4}{2} = 2\ minutes$

In 20 minutes,

20 minutes = $\frac{Total\ time}{Time per box} = \frac{20}{2}$

20 minutes = 10 small boxes

Hank wraps;

3 small boxes = 5 minutes

1 small box = $\frac{5}{3}\ minutes$

In 20 minutes = $\frac{Total\ time}{Time per box} = \frac{20}{5/3}$

$20\ minutes=\frac{20*3}{5}\\20\ minutes=\frac{60}{5}\\20\ minutes= 12\ small\ boxes\\$

In 20 minutes, John can wrap 10 small boxes and Hank can wrap 12 small boxes. So, Hank can wrap more small boxes in 20 minutes than John can.

Keywords: division, multiplication

Learn more about division at:

#LearnwithBrainly

8 0

2 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$