The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
62.8 m^2
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
V = (3.14) ( 2)^2 *5
V = 62.8 m^2
Answer:
<em><u>D.)</u></em>51.837, <em><u>B.)</u></em>51.836, <em><u>A.)</u></em>51.835, <em><u>C.)</u></em>51.736
Step-by-step explanation:
its decreasing in this order
No she didnt. She needs 12% more of .8 yards.
.8 yards x 12% more = 0.096+.8= 0.896 yards to cut
The answer is 1/5, or 0.2, because if you're always putting the slip back in, then there will always by 5 slips to choose from, therefore making the probability 1 out of 5. I hope this helps!