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2 years ago

Which wind blows 30 latitude in both hemisphere almost to the equator

Physics

1 answer:

andriy [413]2 years ago

7 0

Trade winds
Hope it help

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You are designing a new solenoid and experimenting with material for each turn. The particular turn you are working with is a ci

andriy [413]

Answer:

The magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.

Explanation:

Given;

Radius of circular loop, R = 3.00 cm = 0.03 m

Current in the loop, I = 12.0 A

Magnetic field at the center of circular loop is given as;

B = μ₀I / 2R

Where;

μ₀ is constant = 4π x 10⁻⁷ T.m/A

R is the radius of the circular loop

I is the current in the loop

Substitute the given values in the above equation and calculate the magnitude of the magnetic field;

B = (4π x 10⁻⁷ x 12)/ 0.03

B = 5.0272 x 10⁻⁴ T

Therefore, the magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.

8 0

2 years ago

Sound, light, feelings and ideas are not

taurus [48]

I think it’s A, I’m so sorry if I’m wrong.

6 0

2 years ago

What are examples of convection currents?

hram777 [196]

Answer:

I would say all of the above.

Explanation:

Look below for more examples

5 0

2 years ago

The following is current scientific evidence supporting the nebular theory on the formation of the solar system.

Feliz [49]

A.the composition of the inner and outer planets, current observations of star formation, and the motion of the solar system I hope this helps

4 0

3 years ago

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A small sphere has a harge of 9uC and other small sphere has a charge of 4uC.

Helga [31]

Answer:

Electrical force, F = 90 N

Explanation:

It is given that,

Charge on sphere 1, $q_1=9\ \mu C=9\times 10^{-6}\ C$

Charge on sphere 2, $q_1=4\ \mu C=4\times 10^{-6}\ C$

Distance between two spheres, d = 6 cm = 0.06 m

Let F is the electrical force between them. It is given by the formula of electric force which is directly proportional to the product of charges and inversely proportional to the square of distance between them such that,

$F=k\dfrac{q_1q_2}{d^2}$

$F=9\times 10^9\times \dfrac{9\times 10^{-6}\times 4\times 10^{-6}}{(0.06)^2}$

F = 90 N

So, the electrical force between them is 90 N. Hence, this is the required solution.

7 0

2 years ago