Kevin started his science test at 2{:}34\text { p.M.}2:34 p.M.2, colon, 34, start text, space, p, point, m, point, end text and
1 answer:
Answer:
26 Minutes.
Step-by-step explanation:
Kevin started his science test at
He finished the test 75 minutes later.
Now: 75 Minutes = 1 hr 15 Minutes
2:34 + 75 Minutes
=2:34+1:15
=3:49 P.M.
Kevin finished his test by 3:49 P.M.
Kevin has football practice at 4:15 P.M.
Therefore, the time Kevin had between the end of the test and the beginning of football practice
=4:15 P.M.-3:49 P.M.
=26 Minutes.
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Answer:
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.2622
The margin of error is:
M = T*s = 2.2622*0.3 = 0.68
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF
The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF