You can not solve this because the values are different... If the values were both Px and Px or Qx and Qx you will be able to solve the problem but you can not according to the fact that they aren't the same letters. So therefore, this equation has no solution.

Hope this helped!!!

6 0

2 years ago

B) If fencing costs $2.50/yd, determine the<br> costs of building the fence.

siniylev [52]

You didn’t give the rest of the answer hun

8 0

2 years ago

Elizabeth lives in San Francisco and works in Mountain View. In the morning, she has 3 transportation options (take a bus, a cab

mina [271]

Answer:

If Elizabeth randomly chooses her ride in the morning and in the evening, 2/3 is the probability that she'll use a cab exactly one time

3 0

1 year ago

Read 2 more answers

Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would

maxonik [38]

Answer: b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e. 135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137 ,

since 135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146

since 135.8< 146 < 155.9

So , it is usual.

d. 155

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0

2 years ago