There are twice as many students on Mr. Sneed's team as on Mr. Johnson's team. Together, they want to raise 360$ to buy uniforms
2 answers:
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The picture in the attached figure
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
Answer:
15 blocks
Step-by-step explanation:
We can use the Pythagorean theorem to solve the right triangle
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
12^2 + 9^2 = h^2
144+81 = h^2
225= h^2
Taking the square root of each side
sqrt(225) = sqrt(h^2)
15 = h
