The diagram below gives the dimensions of a swimming pool. 18 ft , 20ft, 36ft (c) What is the total area of the swimming pool? E
xplain your reasoning. (d) What is the perimeter of the swimming pool? Explain your reasoning. Answer:
1 answer:
The picture in the attached figure
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
Part 1) <span>What is the total area of the swimming pool?
</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) is
The area of the swimming pool is 592.83 ft²
Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is
122.26 ft
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Answer:
Step-by-step explanation:
a). Since, ΔABC ~ ΔWYZ
Their corresponding sides will be proportional.
--------(1)
By applying Pythagoras theorem in ΔABC,
AB² = AC² + BC²
BC² = AB² - AC²
BC² = (194)² - (130)²
BC² = 20736
BC = 144
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WZ =
WZ = = 0.90
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=
=
Since, ΔABC ~ ΔWYZ,
∠A ≅ ∠W
Therefore, tangent of angle A and angle W will measure .