Question 3 (2 points)

Mathematics

1 answer:

vlada-n [284]2 years ago

8 0

Area = 314.16

circumference = 62.83

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What is the hourly utilization rate of each resource if the bottleneck(s) work nonstop during a 10-hour day?

Bess [88]

Answer:

100%

Step-by-step explanation:

Utilization rate =

Hours worked / total working hours per day

Since the bottle works nonstop during a 10-hour day, it worked 10 hours

Utilization rate in percentage = (10/10)×100%

= 100%

6 0

2 years ago

Miranda made 6.88 pounds of trail mix. She used 4.96 pounds of granola for the mix. Miranda wrote the equation w + 4.96 = 6.88 t

joja [24]

Step 1: to solve this equation first subtract 4.9 from both sides.

w + 4.9 - 4.9 = 6.88 - 4.9

When you reduce that your answer should be w = 1.92

Therefore the weight of ingredients other than granola in Miranda's trail mix is 1.92

5 0

2 years ago

Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25

Oxana [17]

Answer:

Step-by-step explanation:

$\huge {625}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div 25 \\ \\ = \huge {( {5}^{4})}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ = \huge{5}^{ \cancel4 \times \frac{3}{ \cancel8 \: \: \red{ \bold 2}} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} + \frac{1}{2}} \div {5}^{2} \\ \\ \huge= {5}^{ \frac{4}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ 2 } \div {5}^{2} \\ \\ \huge= {5}^{ 2 - 2 } \\ \\ \huge= {5}^{ 0 } \\ \\ \huge= 1$