I think c and b are correct answers
We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
Answer:
Step-by-step explanation:
We'll take this step by step. The equation is
Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:
The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:
Let's rewrite that radical into exponential form:
If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:
On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:
Let's group that radicad into groups of 3's now to make the simplifying easier:
because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:
which is the same as:
Answer:
b
Step-by-step explanation: