In this item, it is unfortunate that a figure, drawing, or illustration is not given. To be able to answer this, it is assumed that these segments are collinear. Points L, M, and N are collinear, and that L lies between MN.
The length of the whole segment MN is the sum of the length of the subsegments, LN and LM. This can be mathematically expressed,
LN + LM = MN
We are given with the lengths of the smalller segments and substituting the known values,
MN = 54 + 31
MN = 85
<em>ANSWER: MN = 85</em>
It took 60 seconds to fax all documents to Gem
Step-by-step explanation:
The simple addition has to be done to solve the given problem
Given
total faxes = 4
Time for fax 1: 
Time for fax 2: 
Time for fax 3: 
Time for fax 4: 
The total time t will be:
Hence,
It took 60 seconds to fax all documents to Gem
Keywords: Time, addition
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-2,3 is (x1,y1) and (4,-5) is (x2,y2) so you do y2-y1/x2-x1
y2-y1 is -5-3 which is -8 and x2-x1 is 4-(-2) which is 6 so you get
-8/6= -4/3
Answer:
1 3/5 miles/hr
Step-by-step explanation:
Let C be the speed of the current
Let D be the distance between Chan's house and the park
We know that Distance, D, is = Speed x Time
-----
Chan's speed going upstream is (8 - C)mph.
That gives us:
D = (8-C)(3 hr)
Chan's speed going downstream is (8+C)mph
So we have:
D = (8+C)(2 hr)
We know that the d is the same for these two equations, so:
(8-C)(3 hr) = (8+C)(2 hr)
24 - 3C = 16 + 2C
5C = 8
C = (8/5) or 1 3/5 mph
The period is equal to 2pi/n, where n is the coefficient of t. In this case pi/2. Therefore the period in this example is 4. Frequency is equal to 1/period. Hence the frequency for this problem is 1/4
