if the sides of a triangle QRS are QR=10X-6, RS=6X-15,QS=X+24, find a range of possible values for X?
1 answer:
X+44 or change ur equations to a better understanding
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M(CE) = 78 + 78*4/26 = 90
y intercept:
Sin(35) = Opp./Hypo
sin(35) = 18/x
so
x = 18/sin(35)
x = 18 / 0.57357644
x = 31.38
x = 31.4
Answer is C. 31.4
<h2>
Answer:</h2>
<em>W=9</em>
<h2>
Step-by-step explanation:</h2>
<em>Hope this helps, here is the answer please mark Brainliest.</em>
Step-by-step explanation:
b=a-80
c=b-61
c=a-141
a+b+c=3a-221=430
3a=651
a=217 & b =137 & c=76