Combined like terms 11d+8
Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet
-29 is 29 bars away from 0. 100 is 100 bars away from 0.
29 + 100 = 129
So the distance between -29 and 100 is 129. The answer is D.
Answer:
1.False
the intervals used to create the histogram is 5.5
2.True
more than 10 hours were used by the students in playing the games
