<h3>Radius = 14cm</h3>
Step-by-step explanation:
Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC
Also, AD ⊥ DC (given), therefore, OPDS is a square.
BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)
therefore, CR = CB - BR = (38 - 27)cm = 11cm
SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.
therefore,
Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).
<h3>Hope it helps you!! </h3>
Answer:
7m² - 5m + 8 + 3/(m+3)
Step-by-step explanation:
7m³+16m²-7m+27
(7m³+21m²-5m²-15m+8m+24+3)/(m+3)
[7m²(m+3) - 5m(m+3) + 8(m+3) + 3]/(m+3)
7m² - 5m + 8 + 3/(m+3)
This is known as "5 take 3", where ordering is not important.
Answer: 2/4=1/2
Step-by-step explanation: 4-2=2. 7-3=4
Answer:
the answer is 9/10
Step-by-step explanation:
I cant draw sorry(┬┬﹏┬┬)╰(*°▽°*)╯
