3x-5x+3 Answer:
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Recall that parallel lines have the same slope.
A line parallel to y= (-3/5)x + 8 would have the same equation EXCEPT for a different constant, C, replacing that '8.'
This new line passes thru (-5,-3). In y= (-3/5)x + C, replace x with -5 and replace y with -3. Then:
-3 = (-3/5)(-5) + C. Find C:
-3 = 3 + C. Thus, C = 6
Thus, the equation of the new line is y= -(3/5)x - 6
Check: Let x = -5 and y = -3. Is the above equation true?
-3 = (-3/5)(-5) - 6
-3 = 3 - 6, or -3 = -3.
L=Lim tan(x)^2/x x->0
Since both numerator and denominator evaluate to zero, we could apply l'Hôpital rule by taking derivatives.
d(tan^2(x))/dx=2tan(x).d(tan(x))/dx = 2tan(x)sec^2(x)
d(x)/dx = 1
=>
L=2tan(x)sec^2(x)/1 x->0
= (2(0)/1^2)/1
=0/1
=0
Another way using series,
We know that tan(x) = x+x^3/3+2x^5/15+.....
then tan^2(x), using binomial expansion gives
x^2+2*x^4/3+.... (we only need two terms)
and again apply l'Hôpital's rule, we have
L=d(x^2+2x^4/3+...)/d(x) = (2x+8x^3/3+...)/1
=0 as x->0
1. 13
2. 20
3. 4
4. 40
5. 4
6. 4
