That’s really easy ask your teacher and also peace happy
Answer:
Not be changed
Option: D
<u>Explanation:</u>
The physical quantity which has both ‘magnitude and direction’ is called vector. These vectors are represented by a line and an arrow, <em>the line represent the magnitude and arrow represent the direction of the physical quantity</em>. The vectors are added and subtracted according to the direction of the vectors.
According to the vector law addition while adding vectors direction and length of the vector is not be changed.<em> If the length of the vector changed the magnitude is also changed while so, while adding vectors length must not be changed.
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Answer:
a. k = (1/k₁ + 1/k₂)⁻¹ b. k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹
Explanation:
Since only one force F acts, the force on spring with spring constant k₁ is F = k₁x₁ where x₁ is its extension
the force on spring with spring constant k₂ is F = k₂x₂ where x₁ is its extension
Let F = kx be the force on the equivalent spring with spring constant k and extension x.
The total extension , x = x₁ + x₂
x = F/k = F/k₁ + F/k₂
1/k = 1/k₁ + 1/k₂
k = (1/k₁ + 1/k₂)⁻¹
B
The force on spring with spring constant k₃ is F = k₃x₃ where x₃ is its extension
Let F = kx be the force on the equivalent spring with spring constant k and extension x.
The total extension , x = x₁ + x₂ + x₃
x = F/k = F/k₁ + F/k₂ + F/k₃
1/k = 1/k₁ + 1/k₂ + 1/k₃
k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹
Answer:
2 ohms
Explanation:
Hi there!
Ohm's law states that 
where V is the voltage, I is the current and R is the resistance.
Plug in the given information (I=7.5, V=15) and solve for R
Divide both sides by 7.5 to isolate R
Therefore, the circuit resistance would be 2 ohms.
I hope this helps!
Answer:
176.4 meters
Explanation:
The first equation is for average velocity. The other three are the constant acceleration equations you'll need to know.
v = at + v₀
v² = v₀² + 2a(x − x₀)
x = x₀ + v₀ t + ½ at²
x is the final position
x₀ is the initial position
v is the final velocity
v₀ is the initial velocity
t is time
a is acceleration
Notice that the first equation is independent of position.
The second equation is independent of time.
The third equation is independent of final velocity.
So knowing which information you <em>don't</em> have will point you to which equation you should use.
Let's begin:
"Which one would be best to find the distance the object fell from free-fall if it fell for six seconds, assuming if fell in the absence of air resistance and it still hasn't hit the ground? Solve this problem and show all steps of work."
We want to find the distance (change in position). We're given the time (t = 6 s) and we're given the acceleration (free fall without air resistance, so a = -9.8 m/s²).
We aren't given the final velocity, so the equation we should use is the third one:
y = y₀ + v₀ t + ½ at²
Unfortunately, we aren't told the initial velocity, but if we assume that the object starts at rest, then v₀ = 0 m/s. Substituting all values:
y = y₀ + (0 m/s) (6 s) + ½ (-9.8 m/s²) (6 s)²
y − y₀ = -176.4 m
The displacement is -176.4 m. Distance is the magnitude of displacement, so we can say the object fell 176.4 meters.
